SKP's Algorithms and Data Structures #6: Java Problem: Active Traders

[Question/Problem Statement is the Property of HackerRank]

Algorithms/Data Structures — [Problem Solving] 
An Institutional Broker wants to Review their Book of Customers to see which are Most Active. Given a List of Trades By "Customer Name, Determine which Customers Account for At Least 5% of the Total Number of Trades. Order the List Alphabetically Ascending By Name."


Example
n = 23
"customers = {"Bigcorp", "Bigcorp", "Acme", "Bigcorp", "Zork", "Zork", "Abe", "Bigcorp", "Acme", "Bigcorp", "Bigcorp", "Zork", "Bigcorp", "Zork", "Zork", "Bigcorp", "Acme", "Bigcorp", "Acme", "Bigcorp", "Acme", "Littlecorp", "Nadircorp"}."

"Bigcorp had 10 Trades out of 23, which is 43.48% of the Total Trades."
"Both Acme and Zork had 5 trades, which is 21.74% of the Total Trades."
"The Littlecorp, Nadircorp, and Abe had 1 Trade Each, which is 4.35%..."

"So the Answer is ["Acme","Bigcorp","Zork"] (In Alphabetical Order) Because only These Three Companies Placed at least 5% of the Trades.


Function Description

Complete the Function mostActive in the Editor Below.

mostActive
has the following parameter:
String customers[n]: An Array Customer Names
(Actual Question Says String Array, But Signature is List of Strings)

Returns String[]: An Alphabetically Ascending Array


Constraints

• 1 < n < 10^5
• 1 < Length of customers[] < 20
• The First Character of customers[i] is a Capital English letter.
• All Characters of customers[i] except for the First One are Lowercase.
• Guaranteed that At least One Customer makes at least 5% of Trades.


Input Format

"The First Line contains an integer, n, The Number of Elements in customers."
"Each Line i of the n Subsequent Lines (where 0 s i< n) contains a string, customers[i]."


Sample Case 0 Input For Custom Testing
20
Omega Alpha Omega Alpha Omega Alpha Omega Alpha Omega Alpha Omega Alpha Omega Alpha Omega Alpha Omega Alpha Omega Beta


Function mostActive       
customers[] size n = 20
customers[] = [As Provided Above]


Sample Output

Alpha
Beta
Omega


Explanation

"Alpha made 10 Trades out of 20 (50% of the Total), Omega made 9 Trades (45% of the Total). and Beta made 1 Trade (5% of the Total). All of them have met the 5% Threshold, so all the Strings are Returned in an Alphabetically Ordered Array."

 

[Explanation of the Solution]
This is Good Practice for the Brain for Problem Solving — Involves Simple Arithmetic and Mathematical Application. Ideally, A Programmer would want to Optimize the Solution in Space and Time (Which I Did Not :-)
 


[Source Code, Sumith Puri (c) 2021 — Free to Use and Distribute]
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
import java.util.stream.IntStream;

/*
 * HackerRank Problem Solving - Ain't a Horse that Can't be Rode
 * Sumith Kumar Puri (c) 2021 - ~ Bengaluru, Karnataka, India ~
 * 
 */
class ActiveTradersLogic {
    
    public static List<String> mostActive(List<String> customers) {

        // How About Arrays or Custom LinkedList for a 'Very Fast' Traversal?
        Map<String, Integer> customerMap = new TreeMap<String, Integer>();
        List<String> solutionStr = new ArrayList<String>();
        int customerMapSize = customers.size();

        for (int i = 0; i < customerMapSize; i++) {

            String customerKey = customers.get(i);

            if (customerMap.containsKey(customerKey)) {

                Integer customerCount = customerMap.get(customerKey);
                customerMap.put(customerKey, ++customerCount);
            } else {
                customerMap.put(customerKey, 1);
            }
        }

        Set<String> customerMapKeys = customerMap.keySet();
        for (String customerKey : customerMapKeys) {

            Integer customerCount = customerMap.get(customerKey);
            double currentCustomerPercent = (double) (customerCount) / (double) customerMapSize;

            if (currentCustomerPercent * 100 >= 5.0) {

                solutionStr.add(customerKey);
            }
        }

        return solutionStr;
    }
}

public class ActiveTraders {
    
    public static final String OUTPUT_PATH = "PROVIDE_ABSOLUTE_INPUT_FILE_NAME";
    
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv(OUTPUT_PATH)));

        int customersCount = Integer.parseInt(bufferedReader.readLine().trim());

        List<String> customers = IntStream.range(0, customersCount).mapToObj(i -> {
            try {
                return bufferedReader.readLine();
            } catch (IOException ex) {
                throw new RuntimeException(ex);
            }
        }).collect(toList());

        List<String> result = ActiveTradersLogic.mostActive(customers);

        bufferedWriter.write(result.stream().collect(joining("\n")) + "\n");

        bufferedReader.close();
        bufferedWriter.close();
    }
}


Happy Problem Solving using Java! 6

 

 

 

 

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